50=-16t^2+63t+4

Solution for 50=-16t^2+63t+4 equation:

50=-16t^2+63t+4

We move all terms to the left:

50-(-16t^2+63t+4)=0

We get rid of parentheses

16t^2-63t-4+50=0

We add all the numbers together, and all the variables

16t^2-63t+46=0

a = 16; b = -63; c = +46;
Δ = b2-4ac
Δ = -632-4·16·46
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-5\sqrt{41}}{2*16}=\frac{63-5\sqrt{41}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+5\sqrt{41}}{2*16}=\frac{63+5\sqrt{41}}{32}
$